Integrand size = 13, antiderivative size = 152 \[ \int \frac {1}{x^{5/3} (a+b x)^3} \, dx=-\frac {10}{3 a^3 x^{2/3}}+\frac {1}{2 a x^{2/3} (a+b x)^2}+\frac {4}{3 a^2 x^{2/3} (a+b x)}+\frac {20 b^{2/3} \arctan \left (\frac {\sqrt [3]{a}-2 \sqrt [3]{b} \sqrt [3]{x}}{\sqrt {3} \sqrt [3]{a}}\right )}{3 \sqrt {3} a^{11/3}}-\frac {10 b^{2/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} \sqrt [3]{x}\right )}{3 a^{11/3}}+\frac {10 b^{2/3} \log (a+b x)}{9 a^{11/3}} \]
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Time = 0.04 (sec) , antiderivative size = 152, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.462, Rules used = {44, 53, 60, 631, 210, 31} \[ \int \frac {1}{x^{5/3} (a+b x)^3} \, dx=\frac {20 b^{2/3} \arctan \left (\frac {\sqrt [3]{a}-2 \sqrt [3]{b} \sqrt [3]{x}}{\sqrt {3} \sqrt [3]{a}}\right )}{3 \sqrt {3} a^{11/3}}-\frac {10 b^{2/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} \sqrt [3]{x}\right )}{3 a^{11/3}}+\frac {10 b^{2/3} \log (a+b x)}{9 a^{11/3}}-\frac {10}{3 a^3 x^{2/3}}+\frac {4}{3 a^2 x^{2/3} (a+b x)}+\frac {1}{2 a x^{2/3} (a+b x)^2} \]
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Rule 31
Rule 44
Rule 53
Rule 60
Rule 210
Rule 631
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2 a x^{2/3} (a+b x)^2}+\frac {4 \int \frac {1}{x^{5/3} (a+b x)^2} \, dx}{3 a} \\ & = \frac {1}{2 a x^{2/3} (a+b x)^2}+\frac {4}{3 a^2 x^{2/3} (a+b x)}+\frac {20 \int \frac {1}{x^{5/3} (a+b x)} \, dx}{9 a^2} \\ & = -\frac {10}{3 a^3 x^{2/3}}+\frac {1}{2 a x^{2/3} (a+b x)^2}+\frac {4}{3 a^2 x^{2/3} (a+b x)}-\frac {(20 b) \int \frac {1}{x^{2/3} (a+b x)} \, dx}{9 a^3} \\ & = -\frac {10}{3 a^3 x^{2/3}}+\frac {1}{2 a x^{2/3} (a+b x)^2}+\frac {4}{3 a^2 x^{2/3} (a+b x)}+\frac {10 b^{2/3} \log (a+b x)}{9 a^{11/3}}-\frac {\left (10 \sqrt [3]{b}\right ) \text {Subst}\left (\int \frac {1}{\frac {a^{2/3}}{b^{2/3}}-\frac {\sqrt [3]{a} x}{\sqrt [3]{b}}+x^2} \, dx,x,\sqrt [3]{x}\right )}{3 a^{10/3}}-\frac {\left (10 b^{2/3}\right ) \text {Subst}\left (\int \frac {1}{\frac {\sqrt [3]{a}}{\sqrt [3]{b}}+x} \, dx,x,\sqrt [3]{x}\right )}{3 a^{11/3}} \\ & = -\frac {10}{3 a^3 x^{2/3}}+\frac {1}{2 a x^{2/3} (a+b x)^2}+\frac {4}{3 a^2 x^{2/3} (a+b x)}-\frac {10 b^{2/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} \sqrt [3]{x}\right )}{3 a^{11/3}}+\frac {10 b^{2/3} \log (a+b x)}{9 a^{11/3}}-\frac {\left (20 b^{2/3}\right ) \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1-\frac {2 \sqrt [3]{b} \sqrt [3]{x}}{\sqrt [3]{a}}\right )}{3 a^{11/3}} \\ & = -\frac {10}{3 a^3 x^{2/3}}+\frac {1}{2 a x^{2/3} (a+b x)^2}+\frac {4}{3 a^2 x^{2/3} (a+b x)}+\frac {20 b^{2/3} \tan ^{-1}\left (\frac {1-\frac {2 \sqrt [3]{b} \sqrt [3]{x}}{\sqrt [3]{a}}}{\sqrt {3}}\right )}{3 \sqrt {3} a^{11/3}}-\frac {10 b^{2/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} \sqrt [3]{x}\right )}{3 a^{11/3}}+\frac {10 b^{2/3} \log (a+b x)}{9 a^{11/3}} \\ \end{align*}
Time = 0.26 (sec) , antiderivative size = 153, normalized size of antiderivative = 1.01 \[ \int \frac {1}{x^{5/3} (a+b x)^3} \, dx=\frac {-\frac {3 a^{2/3} \left (9 a^2+32 a b x+20 b^2 x^2\right )}{x^{2/3} (a+b x)^2}+40 \sqrt {3} b^{2/3} \arctan \left (\frac {1-\frac {2 \sqrt [3]{b} \sqrt [3]{x}}{\sqrt [3]{a}}}{\sqrt {3}}\right )-40 b^{2/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} \sqrt [3]{x}\right )+20 b^{2/3} \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} \sqrt [3]{x}+b^{2/3} x^{2/3}\right )}{18 a^{11/3}} \]
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Time = 0.15 (sec) , antiderivative size = 133, normalized size of antiderivative = 0.88
method | result | size |
derivativedivides | \(-\frac {3}{2 a^{3} x^{\frac {2}{3}}}-\frac {3 b \left (\frac {\frac {11 b \,x^{\frac {4}{3}}}{18}+\frac {7 a \,x^{\frac {1}{3}}}{9}}{\left (b x +a \right )^{2}}+\frac {20 \ln \left (x^{\frac {1}{3}}+\left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}{27 b \left (\frac {a}{b}\right )^{\frac {2}{3}}}-\frac {10 \ln \left (x^{\frac {2}{3}}-\left (\frac {a}{b}\right )^{\frac {1}{3}} x^{\frac {1}{3}}+\left (\frac {a}{b}\right )^{\frac {2}{3}}\right )}{27 b \left (\frac {a}{b}\right )^{\frac {2}{3}}}+\frac {20 \sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (\frac {2 x^{\frac {1}{3}}}{\left (\frac {a}{b}\right )^{\frac {1}{3}}}-1\right )}{3}\right )}{27 b \left (\frac {a}{b}\right )^{\frac {2}{3}}}\right )}{a^{3}}\) | \(133\) |
default | \(-\frac {3}{2 a^{3} x^{\frac {2}{3}}}-\frac {3 b \left (\frac {\frac {11 b \,x^{\frac {4}{3}}}{18}+\frac {7 a \,x^{\frac {1}{3}}}{9}}{\left (b x +a \right )^{2}}+\frac {20 \ln \left (x^{\frac {1}{3}}+\left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}{27 b \left (\frac {a}{b}\right )^{\frac {2}{3}}}-\frac {10 \ln \left (x^{\frac {2}{3}}-\left (\frac {a}{b}\right )^{\frac {1}{3}} x^{\frac {1}{3}}+\left (\frac {a}{b}\right )^{\frac {2}{3}}\right )}{27 b \left (\frac {a}{b}\right )^{\frac {2}{3}}}+\frac {20 \sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (\frac {2 x^{\frac {1}{3}}}{\left (\frac {a}{b}\right )^{\frac {1}{3}}}-1\right )}{3}\right )}{27 b \left (\frac {a}{b}\right )^{\frac {2}{3}}}\right )}{a^{3}}\) | \(133\) |
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Leaf count of result is larger than twice the leaf count of optimal. 244 vs. \(2 (107) = 214\).
Time = 0.24 (sec) , antiderivative size = 244, normalized size of antiderivative = 1.61 \[ \int \frac {1}{x^{5/3} (a+b x)^3} \, dx=\frac {40 \, \sqrt {3} {\left (b^{2} x^{3} + 2 \, a b x^{2} + a^{2} x\right )} \left (-\frac {b^{2}}{a^{2}}\right )^{\frac {1}{3}} \arctan \left (\frac {2 \, \sqrt {3} a x^{\frac {1}{3}} \left (-\frac {b^{2}}{a^{2}}\right )^{\frac {2}{3}} - \sqrt {3} b}{3 \, b}\right ) - 20 \, {\left (b^{2} x^{3} + 2 \, a b x^{2} + a^{2} x\right )} \left (-\frac {b^{2}}{a^{2}}\right )^{\frac {1}{3}} \log \left (b^{2} x^{\frac {2}{3}} + a b x^{\frac {1}{3}} \left (-\frac {b^{2}}{a^{2}}\right )^{\frac {1}{3}} + a^{2} \left (-\frac {b^{2}}{a^{2}}\right )^{\frac {2}{3}}\right ) + 40 \, {\left (b^{2} x^{3} + 2 \, a b x^{2} + a^{2} x\right )} \left (-\frac {b^{2}}{a^{2}}\right )^{\frac {1}{3}} \log \left (b x^{\frac {1}{3}} - a \left (-\frac {b^{2}}{a^{2}}\right )^{\frac {1}{3}}\right ) - 3 \, {\left (20 \, b^{2} x^{2} + 32 \, a b x + 9 \, a^{2}\right )} x^{\frac {1}{3}}}{18 \, {\left (a^{3} b^{2} x^{3} + 2 \, a^{4} b x^{2} + a^{5} x\right )}} \]
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Timed out. \[ \int \frac {1}{x^{5/3} (a+b x)^3} \, dx=\text {Timed out} \]
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Time = 0.29 (sec) , antiderivative size = 154, normalized size of antiderivative = 1.01 \[ \int \frac {1}{x^{5/3} (a+b x)^3} \, dx=-\frac {20 \, b^{2} x^{2} + 32 \, a b x + 9 \, a^{2}}{6 \, {\left (a^{3} b^{2} x^{\frac {8}{3}} + 2 \, a^{4} b x^{\frac {5}{3}} + a^{5} x^{\frac {2}{3}}\right )}} - \frac {20 \, \sqrt {3} \arctan \left (\frac {\sqrt {3} {\left (2 \, x^{\frac {1}{3}} - \left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}}{3 \, \left (\frac {a}{b}\right )^{\frac {1}{3}}}\right )}{9 \, a^{3} \left (\frac {a}{b}\right )^{\frac {2}{3}}} + \frac {10 \, \log \left (x^{\frac {2}{3}} - x^{\frac {1}{3}} \left (\frac {a}{b}\right )^{\frac {1}{3}} + \left (\frac {a}{b}\right )^{\frac {2}{3}}\right )}{9 \, a^{3} \left (\frac {a}{b}\right )^{\frac {2}{3}}} - \frac {20 \, \log \left (x^{\frac {1}{3}} + \left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}{9 \, a^{3} \left (\frac {a}{b}\right )^{\frac {2}{3}}} \]
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Time = 0.29 (sec) , antiderivative size = 150, normalized size of antiderivative = 0.99 \[ \int \frac {1}{x^{5/3} (a+b x)^3} \, dx=\frac {20 \, b \left (-\frac {a}{b}\right )^{\frac {1}{3}} \log \left ({\left | x^{\frac {1}{3}} - \left (-\frac {a}{b}\right )^{\frac {1}{3}} \right |}\right )}{9 \, a^{4}} - \frac {20 \, \sqrt {3} \left (-a b^{2}\right )^{\frac {1}{3}} \arctan \left (\frac {\sqrt {3} {\left (2 \, x^{\frac {1}{3}} + \left (-\frac {a}{b}\right )^{\frac {1}{3}}\right )}}{3 \, \left (-\frac {a}{b}\right )^{\frac {1}{3}}}\right )}{9 \, a^{4}} - \frac {10 \, \left (-a b^{2}\right )^{\frac {1}{3}} \log \left (x^{\frac {2}{3}} + x^{\frac {1}{3}} \left (-\frac {a}{b}\right )^{\frac {1}{3}} + \left (-\frac {a}{b}\right )^{\frac {2}{3}}\right )}{9 \, a^{4}} - \frac {20 \, b^{2} x^{2} + 32 \, a b x + 9 \, a^{2}}{6 \, {\left (b x^{\frac {4}{3}} + a x^{\frac {1}{3}}\right )}^{2} a^{3}} \]
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Time = 0.18 (sec) , antiderivative size = 182, normalized size of antiderivative = 1.20 \[ \int \frac {1}{x^{5/3} (a+b x)^3} \, dx=\frac {20\,b^{2/3}\,\ln \left (540\,{\left (-a\right )}^{19/3}\,b^{8/3}-540\,a^6\,b^3\,x^{1/3}\right )}{9\,{\left (-a\right )}^{11/3}}-\frac {\frac {3}{2\,a}+\frac {10\,b^2\,x^2}{3\,a^3}+\frac {16\,b\,x}{3\,a^2}}{a^2\,x^{2/3}+b^2\,x^{8/3}+2\,a\,b\,x^{5/3}}+\frac {20\,b^{2/3}\,\ln \left (540\,{\left (-a\right )}^{19/3}\,b^{8/3}\,\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )-540\,a^6\,b^3\,x^{1/3}\right )\,\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )}{9\,{\left (-a\right )}^{11/3}}-\frac {20\,b^{2/3}\,\ln \left (540\,{\left (-a\right )}^{19/3}\,b^{8/3}\,\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )+540\,a^6\,b^3\,x^{1/3}\right )\,\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )}{9\,{\left (-a\right )}^{11/3}} \]
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